Boolean
From QB64 Wiki
Boolean statements return True (-1) or False (0) numerical evaluations.
- Basic Returns:
- True evaluations return -1.
- For positive True results, subtract it, multiply it by a negative value or use ABS.
- False evaluations return 0. Watch out for "Division by 0" errors!
Symbol | Condition | Example Usage |
---|---|---|
< | Less than | IF a < b THEN |
> | Greater than | IF a > b THEN |
= | Equal | IF a = b THEN |
<= | Less than or equal | IF a <= b THEN |
>= | Greater than or equal | IF a >= b THEN |
<> | NOT equal | IF a <> b THEN |
- When evaluating a True value, an IF value < 0 statement is NOT necessary for return values not 0.
- Boolean Conditional Operators:
- AND can be used to add extra conditions to a boolean statement evaluation. Both must be True.
- OR can be used to add alternate conditions to a boolean statement evaluation. One must be True.
- Parenthesis are allowed inside of boolean statements to clarify an evaluation.
- Note that Basic returns -1 for True and 0 for False.
Example 1: Using 2 different boolean evaluations to determine a leap year.
INPUT "Enter a year greater than 1583: ", annum$ Y = VAL(annum$) leap1 = (Y MOD 4 = 0 AND Y MOD 100 <> 0) OR (Y MOD 400 = 0) leap2 = (Y MOD 4 = 0) - (Y MOD 100 = 0) + (Y MOD 400 = 0) PRINT "Year = "; annum$, "Leap1 = "; leap1, "Leap2 = "; leap2
- Explanation: Both boolean evaluations will return -1 if the year is a leap year. It is not simply every four years as many people think. That is checked by the first evaluation (Y MOD 4 = 0) of each. In new century years like 1900 (which was not a leapyear) there is only one leap year every 400 years. 100 is used with MOD to see if there is a remainder. When that is true, the boolean return of that part of the first evaluation will be 0. The second returns -1 (which is actually added). In both evaluations the result of (Y MOD 400 = 0) indicates a century leap year.
- Entry year = 2000:
- leap1 = (-1 AND 0) OR -1 = -1 ' the AND evaluation returns False(0) so the OR value is used.
- leap2 = (-1) - (-1) + (-1) = -1 + 1 + -1 = -1
- Entry year = 1900:
- leap1 = (-1 AND 0) OR 0 = 0 OR 0 = 0
- leap2 = (-1) - (-1) + (0) = -1 + 1 + 0 = 0
Example 2: Moving an ASCII character using the arrow keys and boolean statements to determine the new coordinate.
SCREEN 12 COLOR 7 LOCATE 11, 20: PRINT "Using Screen 12 here to be in 80 X 30 coordinates mode" LOCATE 13, 6: PRINT "Simple Example of Alternative programming without IF-THEN-ELSE Statements" LOCATE 15, 1: PRINT "Use the four Cursor keys to move the yellow cursor, text will not be disturbed" LOCATE 17, 12: PRINT "When you END the program with the ESC key, cursor will disappear" cordx% = 40 cordy% = 15 DO oldcordx% = cordx% oldcordy% = cordy% p% = SCREEN(cordy%, cordx%) 'get ASCII character at present position COLOR 14: LOCATE cordy%, cordx%: PRINT CHR$(178); WHILE cordx% = oldcordx% AND cordy% = oldcordy% AND k$ <> CHR$(27) k$ = INKEY$ cordx% = cordx% + (k$ = (CHR$(0) + "K") AND cordx% > 1) + ABS(k$ = (CHR$(0) + "M") AND cordx% < 80) cordy% = cordy% + (k$ = (CHR$(0) + "H") AND cordy% > 1) + ABS(k$ = (CHR$(0) + "P") AND cordy% < 30) WEND COLOR 7: LOCATE oldcordy%, oldcordx%: PRINT CHR$(p%); 'replace overwritten screen characters LOOP UNTIL k$ = CHR$(27)
See also: